Fix literal free when show opcodes is enabled. (#2398)
A literal might be not freed if it is stored in a register, and PARSER_DUMP_BYTE_CODE is enabled, but opcodes are not shown. JerryScript-DCO-1.0-Signed-off-by: Zoltan Herczeg zherczeg.u-szeged@partner.samsung.com
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@@ -636,12 +636,6 @@ parser_generate_initializers (parser_context_t *context_p, /**< context */
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literal_p->prop.length);
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literal_pool_p[literal_p->prop.index] = lit_value;
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}
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if (!context_p->is_show_opcodes
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&& !(literal_p->status_flags & LEXER_FLAG_SOURCE_PTR))
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{
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jmem_heap_free_block ((void *) literal_p->u.char_p, literal_p->prop.length);
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}
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#else /* !PARSER_DUMP_BYTE_CODE */
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if (!(literal_p->status_flags & LEXER_FLAG_UNUSED_IDENT))
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{
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@@ -649,6 +643,14 @@ parser_generate_initializers (parser_context_t *context_p, /**< context */
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}
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#endif /* PARSER_DUMP_BYTE_CODE */
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}
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#ifdef PARSER_DUMP_BYTE_CODE
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if (!context_p->is_show_opcodes
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&& !(literal_p->status_flags & LEXER_FLAG_SOURCE_PTR))
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{
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jmem_heap_free_block ((void *) literal_p->u.char_p, literal_p->prop.length);
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}
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#endif /* PARSER_DUMP_BYTE_CODE */
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}
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else if ((literal_p->type == LEXER_FUNCTION_LITERAL)
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|| (literal_p->type == LEXER_REGEXP_LITERAL))
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