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Fix Date construct helper

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Correct behaviour of step 8, 15.9.3.1, ECMA-262 v5.1.
 - Change ToInt32(y) to ToInteger(y).
 - If ToInteger(y) is not between 0 and 99 then yr = y

Related issue: #1071

JerryScript-DCO-1.0-Signed-off-by: Hanjoung Lee hanjoung.lee@samsung.com

JerryScript-DCO-1.0-Signed-off-by: Hanjoung Lee hanjoung.lee@samsung.com
This commit is contained in:
Hanjoung Lee
2016-06-15 10:34:37 +09:00
parent 372a2bb40b
commit 1c43e5b02b
3 changed files with 28 additions and 7 deletions
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jerry-core/ecma/base/ecma-helpers-number.c
+2
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@@ -619,6 +619,8 @@ ecma_number_negate (ecma_number_t num) /**< ecma-number */
ecma_number_t
ecma_number_trunc (ecma_number_t num) /**< ecma-number */
{
JERRY_ASSERT (!ecma_number_is_nan (num));
uint64_t fraction;
int32_t exponent;
const int32_t dot_shift = ecma_number_get_fraction_and_exponent (num, &fraction, &exponent);
jerry-core/ecma/builtin-objects/ecma-builtin-date.c
+3 -7
View File
@@ -136,18 +136,14 @@ ecma_date_construct_helper (const ecma_value_t *args, /**< arguments passed to t
if (ecma_is_value_empty (ret_value))
{
if (!ecma_number_is_nan (year) && !ecma_number_is_infinity (year))
if (!ecma_number_is_nan (year))
{
/* 8. */
int32_t y = ecma_number_to_int32 (year);
ecma_number_t y = ecma_number_trunc (year);
if (y >= 0 && y <= 99)
{
year = (ecma_number_t) (1900 + y);
}
else
{
year = (ecma_number_t) y;
year = 1900 + y;
}
}