Implement EscapeRegExpPattern method (#3543)
the algorithm is based on ECMA-262 v6, 21.2.3.2.4 JerryScript-DCO-1.0-Signed-off-by: Adam Szilagyi aszilagy@inf.u-szeged.hu
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// Copyright JS Foundation and other contributors, http://js.foundation
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//
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// Licensed under the Apache License, Version 2.0 (the "License");
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// you may not use this file except in compliance with the License.
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// You may obtain a copy of the License at
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//
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// http://www.apache.org/licenses/LICENSE-2.0
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//
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// Unless required by applicable law or agreed to in writing, software
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// distributed under the License is distributed on an "AS IS" BASIS
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// WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
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// See the License for the specific language governing permissions and
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// limitations under the License.
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var regexp = /fooBar/ig;
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assert(regexp.source === 'fooBar');
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assert(new RegExp().source === '(?:)');
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assert(new RegExp('/foo/').source === '\\/foo\\/');
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assert(new RegExp('/foo/').source.length === 7);
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assert(new RegExp('bar', 'ug').source === 'bar');
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assert(new RegExp('/\?/').source === '\\/?\\/');
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assert(new RegExp('/\?/').source.length === 5);
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assert(new RegExp('\n').source === '\\n');
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assert(new RegExp('\r').source === '\\r');
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assert(new RegExp('\u2028').source === '\\u2028');
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assert(new RegExp('\u2029').source === '\\u2029');
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assert(new RegExp('/\n/').source === '\\/\\n\\/');
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assert(new RegExp('/\n/').source.length === 6);
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assert(new RegExp(/\/\//).source === '\\/\\/');
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assert(new RegExp(/\?\//g).source === '\\?\\/');
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